Integrand size = 15, antiderivative size = 102 \[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\frac {2}{9} x \sqrt [4]{-2+3 x^2}+\frac {2\ 2^{3/4} \sqrt {\frac {x^2}{\left (\sqrt {2}+\sqrt {-2+3 x^2}\right )^2}} \left (\sqrt {2}+\sqrt {-2+3 x^2}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{-2+3 x^2}}{\sqrt [4]{2}}\right ),\frac {1}{2}\right )}{9 \sqrt {3} x} \]
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Time = 0.03 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {327, 240, 226} \[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\frac {2\ 2^{3/4} \sqrt {\frac {x^2}{\left (\sqrt {3 x^2-2}+\sqrt {2}\right )^2}} \left (\sqrt {3 x^2-2}+\sqrt {2}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{3 x^2-2}}{\sqrt [4]{2}}\right ),\frac {1}{2}\right )}{9 \sqrt {3} x}+\frac {2}{9} \sqrt [4]{3 x^2-2} x \]
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Rule 226
Rule 240
Rule 327
Rubi steps \begin{align*} \text {integral}& = \frac {2}{9} x \sqrt [4]{-2+3 x^2}+\frac {4}{9} \int \frac {1}{\left (-2+3 x^2\right )^{3/4}} \, dx \\ & = \frac {2}{9} x \sqrt [4]{-2+3 x^2}+\frac {\left (4 \sqrt {\frac {2}{3}} \sqrt {x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {x^4}{2}}} \, dx,x,\sqrt [4]{-2+3 x^2}\right )}{9 x} \\ & = \frac {2}{9} x \sqrt [4]{-2+3 x^2}+\frac {2\ 2^{3/4} \sqrt {\frac {x^2}{\left (\sqrt {2}+\sqrt {-2+3 x^2}\right )^2}} \left (\sqrt {2}+\sqrt {-2+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{-2+3 x^2}}{\sqrt [4]{2}}\right )|\frac {1}{2}\right )}{9 \sqrt {3} x} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 4.99 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.56 \[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\frac {2 x \left (-2+3 x^2+\sqrt [4]{2} \left (2-3 x^2\right )^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {3}{2},\frac {3 x^2}{2}\right )\right )}{9 \left (-2+3 x^2\right )^{3/4}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 2.19 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.41
method | result | size |
meijerg | \(\frac {2^{\frac {1}{4}} {\left (-\operatorname {signum}\left (-1+\frac {3 x^{2}}{2}\right )\right )}^{\frac {3}{4}} x^{3} {}_{2}^{}{\moversetsp {}{\mundersetsp {}{F_{1}^{}}}}\left (\frac {3}{4},\frac {3}{2};\frac {5}{2};\frac {3 x^{2}}{2}\right )}{6 \operatorname {signum}\left (-1+\frac {3 x^{2}}{2}\right )^{\frac {3}{4}}}\) | \(42\) |
risch | \(\frac {2 x \left (3 x^{2}-2\right )^{\frac {1}{4}}}{9}+\frac {2 \,2^{\frac {1}{4}} {\left (-\operatorname {signum}\left (-1+\frac {3 x^{2}}{2}\right )\right )}^{\frac {3}{4}} x {}_{2}^{}{\moversetsp {}{\mundersetsp {}{F_{1}^{}}}}\left (\frac {1}{2},\frac {3}{4};\frac {3}{2};\frac {3 x^{2}}{2}\right )}{9 \operatorname {signum}\left (-1+\frac {3 x^{2}}{2}\right )^{\frac {3}{4}}}\) | \(53\) |
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\[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{2}}{{\left (3 \, x^{2} - 2\right )}^{\frac {3}{4}}} \,d x } \]
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Result contains complex when optimal does not.
Time = 0.44 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.30 \[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\frac {\sqrt [4]{2} x^{3} e^{- \frac {3 i \pi }{4}} {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{4}, \frac {3}{2} \\ \frac {5}{2} \end {matrix}\middle | {\frac {3 x^{2}}{2}} \right )}}{6} \]
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\[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{2}}{{\left (3 \, x^{2} - 2\right )}^{\frac {3}{4}}} \,d x } \]
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\[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{2}}{{\left (3 \, x^{2} - 2\right )}^{\frac {3}{4}}} \,d x } \]
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Timed out. \[ \int \frac {x^2}{\left (-2+3 x^2\right )^{3/4}} \, dx=\int \frac {x^2}{{\left (3\,x^2-2\right )}^{3/4}} \,d x \]
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